std::chrono::time_point<Clock,Duration>::time_since_epoch
来自cppreference.com
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(C++11 起) (C++14 起为 constexpr) |
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返回表示 *this 与 clock 的纪元间的时间量的 std::chrono::duration。
参数
(无)
返回值
此 time_point 与 clock 的纪元间的时间量。
示例
运行此代码
#include <chrono>
#include <ctime>
#include <iostream>
int main()
{
const auto p0 = std::chrono::time_point<std::chrono::system_clock>{};
const auto p1 = std::chrono::system_clock::now();
const auto p2 = p1 - std::chrono::hours(24);
std::time_t epoch_time = std::chrono::system_clock::to_time_t(p0);
std::cout << "纪元: " << std::ctime(&epoch_time);
std::time_t today_time = std::chrono::system_clock::to_time_t(p1);
std::cout << "今天: " << std::ctime(&today_time);
std::cout << "纪元起小时数: "
<< std::chrono::duration_cast<std::chrono::hours>(
p1.time_since_epoch()).count()
<< '\n';
std::cout << "昨天,纪元起小时数: "
<< std::chrono::duration_cast<std::chrono::hours>(
p2.time_since_epoch()).count()
<< '\n';
}
可能的输出:
纪元: Thu Jan 1 00:00:00 1970
今天: Fri Jun 30 10:44:11 2017
纪元起小时数: 416338
昨天,纪元起小时数: 416314