std::chrono::time_point<Clock,Duration>::min
来自cppreference.com
| (C++20 前) | ||
| |
(C++20 起) | |
返回拥有最小可能时长的 time_point,即 time_point(duration::min())。
参数
(无)
返回值
最小的可能的 time_point。
示例
运行此代码
#include <chrono>
#include <iomanip>
#include <iostream>
#include <ratio>
#include <string>
constexpr auto steady_min = std::chrono::steady_clock::time_point::min();
void animate_frame_at_time_offset(double game_time)
{
std::cout << std::string(static_cast<int>(game_time) % 10 + 1, '*') << '\n';
}
int main()
{
auto last_frame = steady_min;
std::chrono::duration<double, std::micro> game_time{0.0};
for (int n = 0; n < 5; ++n)
{
const auto current_frame = std::chrono::steady_clock::now();
// initialize timer if first frame ever:
if (last_frame == steady_min)
last_frame = current_frame;
game_time += current_frame - last_frame;
std::cout << "Drawing frame at " << std::setprecision(10)
<< std::setw(8) << game_time.count() << " μs ";
animate_frame_at_time_offset(game_time.count());
}
}
可能的输出:
Drawing frame at 0 μs *
Drawing frame at 134.499 μs *****
Drawing frame at 274.337 μs *****
Drawing frame at 416.571 μs *******
Drawing frame at 561.124 μs **